matched pairs and paired data

$H_0: \mu_d > 0$ and $H_a: \mu_d = 0$, with $\bar{x}_d = 2.4$ and $s_d \approx 1.78$

$H_0: \mu_d = 0$ and $H_a: \mu_d > 0$, with $\bar{x}_d = 2.4$ and $s_d \approx 1.78$

$H_0: \mu_d = 0$ and $H_a: \mu_d > 0$, with $\bar{x}_d = 2.4$ and $s_d \approx 1.40$

$H_0: \mu_d = 0$ and $H_a: \mu_d \neq 0$, with $\bar{x}_d = 2.4$ and $s_d \approx 1.78$

$H_0: \mu_1 = \mu_2$ and $H_a: \mu_1 < \mu_2$, with $\bar{x}_d = 2.4$ and $s_d \approx 1.78$

$t \approx -0.36$, and the mean difference is not shown to differ from 0

$t \approx -1.51$, and the mean difference is not shown to differ from 0

$t \approx -6.41$, and the mean difference is shown to differ from 0

$t \approx -1.51$, and the mean difference is shown to differ from 0

$t \approx -1.51$, and the second program is shown to be the more effective one